Writing a set in the form of intersection of two sets

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I need to write the following set in the form of intersection of two sets, each of which is the product of two Borel sets (in on dimension).
$\{(x,y)\ |\ x < y \ \wedge \ y < k\}$

In other words, I want to find A, B , C and D where

$\{(x,y)\ |\ x < y \ \wedge \ y < k\} = (A \times \ B) \ \cap \ (C \ \times \ D) $

where A, B, C and D are Borel sets on the real line (one dimension).

I can write the set in the form of intersection as $ \{(x,y)\ |\ x < y \ \wedge \ y < k\} = \{(x,y)\ | \ x<y\}\ \cap \ \{(x,y)\ |\ y<k\} $

but I cannot manage to write the new sets (on the right) in the form of the product of two borel sets on the real line (one dimension real line)

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It can't be done. It requires that $A\supset (-\infty,k)\subset C,$ otherwise for some $r<k$ we have $(r, (r+k)/2)\not \in A\times B$ or $(r,(r+k)/2)\not \in C\times D.$ Similarly, it requires that $B\supset (-\infty,k)\subset D.$ But then $ (A\times B)\cap (C\times D)\supset (-\infty,k)\times (-\infty,k).$

However $S=\{(x,y):k>y>x\}$ is the union of countably many "Borel rectangles", for example $S=\cup \{(-\infty,q)\times (q,k): k>q\in \Bbb Q\}.$ Or we can observe that $S$ is open in $\Bbb R^2,$ and $B=\{(a,b)\times (c,d): a,b,c,d\in \Bbb Q\}$ is a countable base (basis) for the topology on $\Bbb R^2$, so $S=\cup \{b\in B:b\subset S\}.$