$\;x^{52}=x^{-4}\cdot r^7\;$ what will be the value of r?

Question

If $x^{52}=x^{-4}\cdot r^7$ then what will be the value of $r$?

Answer 1

Multiplying by $$x^4\neq 0$$ we get $$x^{56}=r^7$$ so $$r=\sqrt[7]{x^{56}}$$