xor values of character and space vs xor value of character and character

Question

How do i prove that xor of character and character is always less than 64 while xor of a space and a character is greater than equal to 64 .

NOTE :that all english characters have ascii in [64, 127] but ascii of space is 32

Answer 1

Binary representations of several numbers, using seven binary digits: $$0_{10}=0000000_2\\1_{10}=0000001_2\\2_{10}=0000010_2\\4_{10}=0000100_2\\8_{10}=0001000_2\\16_{10}=0010000_2\\32_{10}=0100000_2\\64_{10}=1000000_2$$ Then, following @AseemBaranwal 's comment, all characters have $1$ in the left most position, while space has $0$. So space XOR character will have $1$ in the left more position, so it is greater (or equal) than $64$. If you have character XOR character, in the left most position you have $1$ XOR $1=0$.