$1.87= x/(0.80-x)$ Easy question with one difficult step

Question

I am doing some very basic algebra work, and one of the examples has the question and how to solve for $x$. The answer looks like $$1.87=\frac{x}{0.80-x}$$ multiply both sides by $0.80-x$ simplified $$1.87(0.80-x)=x$$ which expanded looks like $$1.496-1.87x=x$$ subtract $1.496$ from both sides

$$-1.87x=x-1.496$$ subtract $x$ from both sides $$-1.87x-x=x-1.496-x$$ simplified $$-2.87x=-1.496$$ solved $$\frac{-2.87x}{-2.87} =\frac{-1.496}{-2.87}$$ $$x=0.52125$$

I can follow all of this and understand the steps, but where I am getting lost is when $-1.87x$ becomes $-2.87x$. Why does this happen? Would subtracting an $x$ just create $-1.87$?

Answer 1

$$-1.87-1=-2.87$$

If it helps

$$-1.87-1=-(1.87+1)=-2.87$$

Answer 2

In the expression $-1.87x-x $, if there is no coefficient of the second term $x$, the coefficient of that term is understood to be $1$. Thus, $-1.87x - x$ can be rewritten as $$-1.87x - 1x$$$$ = (-1.87-1)x$$$$= -2.87x$$