If a cock is worth 5 qians, a hen 3 qians, and three chicks together 1 qian, how many cocks, hens, and chicks, totaling 100, can be bought for 100 coins?
So if , $x$ is the number of cocks, $y$ is the number of hens, $z$ the number of chicks such that
$5x + 3y + z/3 = 100$
$x + y + z = 100$
Then i further solve it and find only three possible solutions of it which satisfying all requirement
But then why my book is saying this problem as a " indeterminate problem " or am i doing anything wrong ?