2 $\times$ 2 Symmetry matrices of a square

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I have a square with vertices at the points (2,2), (-2,2),(-2,-2) and (2,-2). I am looking to find the 8 2 $\times$ 2 matrices corresponding to the square symmetries. I have used this resource http://mathonline.wikidot.com/the-group-of-symmetries-of-the-square to calculate the rotational symmetries, however, I can not figure out how to express the flip (reflection) symmetries in matrix form. Any help would be greatly appreciated!

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Hint:

look at the matrices: $$ \begin{bmatrix} -1&0\\ 0&1 \end{bmatrix} \qquad \begin{bmatrix} 1&0\\ 0&-1 \end{bmatrix} \qquad \begin{bmatrix} 0&1\\ 1&0 \end{bmatrix} \qquad \begin{bmatrix} 0&-1\\ -1&0 \end{bmatrix} $$

and the way these matrices transform the vectors of the basis $[1,0]^T$ and $[0,1]^T$.