$3$ Triangles and a quadrilateral

Question

In the following diagram, in $\Delta ABC$, $CD$ and $BE$ are two cevians intersecting it point $O$.
Area of $\Delta BOD = 3, \Delta BOC = \Delta COE = 7$. What is the area of $ADOE$.
Note: I can't find a way to solve this. Any hint will be helpful.

Answer 1

Hint: let $x,y$ be the area of $\triangle ADO, \triangle AEO$ respectively. Then: $O$ is the midpoint of $BE$ (why).So: $x+3 = y$.And $\dfrac{x}{y+7} = \dfrac{3}{7}$. Can you continue? Once you solve this system of equations , you know what $x,y$ are and the area of the quadrilateral is $x+y$.