If in a triangle ABC, ∠B = 2∠C and the bisector of ∠B meets CA in D, then the ratio BD : DC would be equal to?

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Options :

(a) AD : AC (b) AB : AD (c) AB : AC (d) AC : AB

? i think all options are wrong, correct answer should be 1:1 or AB : AC ?

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I think you are right. All options are wrong.

a) $AD=AC$ is impossible;

b) If $AB=AD$ then $\measuredangle ADB=\measuredangle C$, which is impossible and

c), d) If $AB=AC$ then $\measuredangle C=\measuredangle ABC$, which is impossible.