If 7 in 32 bit binary form is:
00000000000000000000000000000111
I would like to perform right arithmetic shift (>>) by 16 so what would the binary representation look like then? I'm a bit confused on this.
2026-04-03 22:33:46.1775255626
32 bit representations and shifting
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With each arithmetic shift right, the lowest bit falls off the end, the other bits move down one position, and the sign bit (0 here) propagates down. So after only 3 shifts, all bits are 0, and each of the remaining shifts result in zero as well. So: the result is 0 in every bit position.