I must make 1 addition (x+y=z), 1 subtraction (x-y=z), 1 multiplication (x*y=z), and 1 division (x/y=z) equation with the following numbers. All the numbers must be used to fill x, y, and z of each equation. x, y, and z can consist be 1, 2, or 3-digit numbers.
0-4 available
1-9 available
2-1 available
3-2 available
5-1 available
6-1 avilalble
7-0 available
8-1 available
9-1 available
Thanks!
There is no magic here, just guess and try. I find $11+18=29, 11-6=5, 100*0=0,31/1=31$ as one of what must be many solutions.