So I have to solve this problem:
Problem 7. In a basin of saltwater of $60\,\text{m}^3$ the amount of water sank by means of evaporation from $95.5\%$ to $93\%.$ How much saltwater remains in the basin?
I calculated $60 \times 0.045 = 2.7$ So therefore $60-2.7 = 57.3$
And $60 \times 0.07 = 4.7$
So there should be $52.6\, \text{m}^3$ still in the basin and the water sank by $2.$
Makes sense for me. The answer however is $28.57$ according to the solutions, what am I doing wrong or rather think wrong?