$4x + 6y =36$ represents a straight line graph. Find $x$ when $y=0$

Question

$4x + 6y =36$ represents a straight line graph. Find

i) $x$ when $y=0$

ii) $y$ when $x=0$

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I don't know how to start this. I was thinking of

$6y= 4x -36$ or $y=(m)(x)=0$

but it's all confusing and I don't know where to put the numbers

Answer 1

We have the following equation of the straight line: $$4x+6y=36$$ 1. Setting $y=0$, we get $$4x+6(0)=36\iff x=\frac{36}{4}=9$$

$$\bbox[5px, border:2px solid #C0A000]{\color{red}{x=9}}$$

2. Setting $x=0$, we get $$4(0)+6y=36\iff y=\frac{36}{6}=6$$ $$\bbox[5px, border:2px solid #C0A000]{\color{red}{y=6}}$$

Answer 2

Plug in $y=0$:

$$4x+6(0)=36$$

This is the same as

$$4x=36$$

Then divide by $4$

$$x=9$$

Do the same for the other.

Answer 3

You can solve this problem by simple substitution.

Given $$ 4x + 6y =36 ,$$

1. You need to find $x $ when $y=0$. Substituting $y=0$ into original equation, we get $$4x + 6 \!\cdot\!0 = 36 \implies 4x = 36 \implies x = 9,$$ so that for $y=0$ the answer is $x=9$.

2. Similarly, substituting $x = 0$ into $4x + 6y =36$, we get $$ 4\! \cdot \! 0 + 6y =36 \implies 6 y = 36 \implies y = 6, $$ so that for $x=0$ the answer is $y=6$.

Answer 4

$4x+6y=36$

Put in this equation $x=0$ we get $6y=36 $

dividing both sides by $6$ we get $y=6$.

Now put $y=0$ in equation $4x+6y=36$

we get $4x=36$

dividing both sides by $4$ we get $x=9$.

Answer 5

$4x+6y=36$

Put $x=0$,$4\times 0+6y=36\Rightarrow 6y=36\Rightarrow y=6$

Put $y=0$,$4x+6\times 0=36\Rightarrow 4x=36\Rightarrow x=9$