A 1968 AHSME problem with exponents

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Given the three numbers $x,y=x^x,z=x^{x^x}$ with $.9<x<1.0$. Arranged in order of increasing magnitude, they are:

$\text{(A) } x,z,y\quad \text{(B) } x,y,z\quad \text{(C) } y,x,z\quad \text{(D) } y,z,x\quad \text{(E) } z,x,y$

Hi, hope you are doing well. I was solving this 1968 AHSME Problem 29.

Unfortunately, I could not solve this problem. Any help would be appreciated. Also, I was wondering what would happen if say $0<x<0.9$ or $x<0$ and other cases. Please help.

My Thought Process

Since $x<1.0$, $x^x$ must be less than $x$ but I couldn't reason out the further.

Also, in the case $x > 1$, $x^{x^x} > x^x > x$ as it increases due to $x$ being greater than $1$.

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$$1>x^{1-x},$$ which gives $$x^x>x,$$ which gives $$x^{x^x}<x^x.$$ Id est, it's enough to compare $x^{x^x}$ and $x$.

Since, $$x^x<1,$$ we obtain $$x^{x^x}>x.$$ Thus, $$x^x>x^{x^x}>x.$$

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Hint: Compare $\ln x$ , $\ln y$ , $\ln z$