Suppose $A,B\in \mathbb{R}^{n \times n}$ are non negative definite matrices. We have already know that $A-B$ is also non negative definite. How to show that $\det(A) \geq \det(B)$, if $\det(A)$ means the determinant of matrix $A$?
2026-03-25 18:50:14.1774464614
$A$, $B$, and $A-B$ are non negative definite matrices. How to show that $\det(A) \geq \det(B)$?
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