What is the necessary and sufficient condition on matrix $A$ such that $h(x) = Ax$ is lipschitz continuous ? $A $ is a $m \times n$ matrix and $x$ is $n \times 1$ matrix.
2026-03-26 16:02:12.1774540932
A basic doubt on Lipschitz continuity
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Always will be Lipschitz: $$\|A(x-y)\|\le|||A|||\,\|x-y\|,$$ with $|||\cdot|||$ the operator norm associated to $\|\cdot\|$.