I wanted to find a recurrence formula for
$(1, 1497), (2, 1585), (3, 1587), (4, 1675), (5, 1677), (6, 1765), (7, 1767), (8, 1855), (9, 1857), (10, 1945), (11, 1947), (12, 1997), (13, 2494), (14, 2496), (15, 2584), (16, 2586), (17, 2674), (18, 2676), (19, 2764), (20, 2766), (21, 2854), (22, 2856), (23, 2944), (24, 2946), (25, 2996), (26, 3493)$
I don't know what should be added for jump between eleven and twelve term.
The formula I've got looks like this
$F_{n} = 1495 + \frac{1}{2} (90 n + 43 (-1)^n - 43) + 497 \left \lfloor \frac{n}{14} \right \rfloor$
How the recurrence formula should look like?