A different definition of coproduct in a category

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I am following Pavel et al book "Tensor Categories". They write that an additive category is a category $\mathcal{C}$ such that:

enter image description here

My problem is with (A3). i know that what they are trying to say is that all bicoproducts exist. But I do not see how that is equivalent to what they wrote: as far as I understand, the coproduct $X_1\rightarrow X_1\sqcup X_2\leftarrow X_2$ is such that for every other pair of arrows $X_1\rightarrow Y\leftarrow X_2$ we have an unique arrow $f$ such that enter image description here

commutes.

I do not see how to connect this with what they say in (A3).

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The author is here using to their advantage the fact that there is an additive structure.

Indeed, let me use the notations of A3, and let $Z$ be an object with maps $f_i: X_i\to Z$. Then consider the map $Y\to Z$ defined by $f=f_1\circ p_1+f_2\circ p_2$.

One may check at once that $f\circ i_1 = f_1\circ p_1\circ i_1 + f_2\circ p_2 \circ i_1 = f_1 + f_2\circ 0 = f_1$ (indeed one may prove that $p_2\circ i_1 = 0$ using the fact that $i_2$ is a monomorphism), and similarly $f\circ i_2 = f_2$, and if $g$ satisfies those equations, then $g= g\circ i_1\circ p_1 + g\circ i_2\circ p_2 = f_1\circ p_1 + f_2\circ p_2 = f$, thus our map $f$ is unique.

This shows that $(Y,i_1,i_2)$ is a coproduct in the usual sense. Similarly you may prove that $(Y,p_1,p_2)$ is a product in the usual sense. This is what makes it a biproduct.