$A\leq B \leq C \implies B\leq A^{1-\alpha} C^{\alpha}$ for $\alpha \in (0,1)$?

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Let $A, B, C \in (0, \infty)$ such that $A\leq B \leq C.$

Can we say that $B\leq A^{1-\alpha} C^{\alpha}$ for $\alpha \in (0,1)$?

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Try $A=1$, $B=2$, $C=3$ and $\alpha=\frac{1}{2}$