How you do apply the binomial theorem to deduce that $(\frac34)^{\frac45}=0.7944$ correct to $4$dp?
I've written $(\frac34)^{\frac45}=((1-\frac14)^5)^{\frac14}$ then expanded the RHS to get
$(1-\binom{5}{1}(\frac14)+\binom{5}{2}(\frac14)^2-\binom{5}{3}(\frac14)^3+\binom{5}{4}(\frac14)^4-(\frac14)^5)^{\frac14}$ But I don't know how to go further or if I'm even doing this right