A Theorem on Compactness By Munkres

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I'm a beginner on topology. I was reading Munkres' Analysis on Manifolds when I came across the following theorem (or a definition of compactness).

A subspace $X$ of $R^n$ is compact if and only if for every collection of sets open in $X$ whose union is $X$, there is a finite subcollection whose union equals $X$.

Is it generally true that for every compact subspace $X$ of $R^n$ there exists a finite collection of sets open in $X$ whose union equals $X$?

There are many finite unions of open sets (in $X$) that contain $X$, but it is trivial that we can really find one among those unions that is equal to $X$?

Any help will be appreciated.

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Take any finite cover of $X$ in $\mathbb{R}^n$ and take the intersections of those sets with $X$. Then those will be open in $X$ (in the subspace topology - this is probably how he means you to interpret this) and their union will be $X$.