Nonclosed set in $ \mathbb{R}^2 $

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I have a set of points $(x, y) \in \mathbb{R}^2$ given by inequality: $|y| \leq \sin\left(\frac{1}{x}\right)$. And it's argued that this set isn't closed. I don't understand why. As I understand, this set is points under the plot of $y = \sin\left(\frac{1}{x}\right),$ starting from $x = \frac{1}{\pi}$ and above the plot of $y = -\sin\left(\frac{1}{x}\right)$, starting from $x = \frac{1}{\pi}$.

Help me, please, to find a limit (or boundary) point of this set which is not in it.