In Mathworld's article Gamma function, in line (96), we find the formula,
$\sum_{k=0}^\infty (8k+1)\left(\frac{\Gamma(k+\frac{1}{4})}{k!\;\Gamma(\frac{1}{4})}\right)^4 = 2^{3/2}\frac{1}{\sqrt{\pi}\,\left(\Gamma(3/4)\right)^2}$
On a whim, I evaluated the LHS and RHS using Mathematica to 100-digit precision, and found the first few digits as,
$\text{LHS} = 1.062679901\dots$
$\text{RHS} = 1.062679899\dots$
Ahem, they don't match. If it is a typo, then I find it interesting it is exceedingly close.
So what is the problem? 1) Did I input it in Mathematica wrongly? 2) Is there a typo, or misplaced symbol by authors after Ramanujan (Weisstein gives Hardy et al as references) 3) Or was Ramanujan just mistaken?
The series in question converges slowly, $(8k+1) \left( \frac{(1/4)_k}{k!} \right)^4 \sim \frac{8}{k^2 \Gamma^4(1/4)}$, hence it may be that you have not computed enough terms.
The sum represents a value of a hypergeometric function: $$ \sum_{k=0}^\infty (8k+1) \left( \frac{(1/4)_k}{k!} \right)^4 = {}_4F_3\left( \frac{1}{4},\frac{1}{4}, \frac{1}{4}, \frac{1}{4}; 1,1,1 | 1\right) - \frac{1}{32} {}_4F_3\left( \frac{5}{4},\frac{5}{4}, \frac{5}{4}, \frac{5}{4}; 2,2,2 | 1\right) $$ Evaluating these numerically agrees with the expression in terms of $\Gamma$ constant: