A way to express 100 by using the first four natural numbers

Question

Is there a way to express 100 by using the first four natural numbers in order?

The numbers 1, 2, 3, 4 can be linked by using $+$, $-$, $\times$, $\div$, $($ $)$, $!$ and exponents are also allowed. But you are not allowed to leave the integers.

Examples: $$-1+(2+3)^4=624$$ $$(1!+2)^{3^4}= large$$

Answer 1

Seems more like a Puzzling.SE question to me but here's a CW post for others to edit. 79/100 complete

Number	Expression
1	$-1+2\cdot3-4$
2	$1+2+3-4$
3	$1+2\cdot3-4$
4	$1+2-3+4$
5	$1^{2\cdot3}+4$
6	$1-2+3+4$
7	$-1+2\cdot3!-4$
8	$-1+2+3+4$
9	$1\cdot2+3+4$
10	$1+2+3+4$
11	$1-2+3\cdot4$
12	$1^2\cdot3\cdot4$
13	$1+2+3!+4$
14	$1\cdot(2+3\cdot4)$
15	$-(1+2)!-3+4!$
16	$-1\cdot2^3+4!$
17	$1-2^3+4!$
18	$-1\cdot2\cdot3+4!$
19	$-1 + (2+3)\cdot 4$
20	$(-1+2+3)!-4$
21	$-(1+2)!+3+4!$
22	$-(-1^2+3)!+4!$
23	$-(1^{2\cdot3})+4!$
24	$-1-2+3+4!$
25	$-(1\cdot2)+3+4!$
26	$1-2+3+4!$
27	$-1-2+3!+4!$
28	$-1+2+3+4!$
29	$1-2+3!+4!$
30	$1+2+3+4!$
31	$-1+2+3!+4!$
32	$1\cdot2^3+4!$
33	$1+2+3!+4!$
34
35	$-1+2!\cdot3!+4!$
36	$1\cdot2!\cdot3!+4!$
37	$1+2!\cdot3!+4!$
38
39	$-1+2^{3!}-4!$
40	$ (1+2)! \cdot 3! +4$
41	$1+2^{3!}-4!$
42	$(1+2)!\cdot(3+4)$
43	$1+2\cdot(-3+4!)$
44	$(-1+2\cdot3!)\cdot4$
45
46
47	$-1+2\cdot3!\cdot4$
48	$(1^2+3)!+4!$
49	$1+2\cdot3!\cdot4$
50
51	$(1+2)^3+4!$
52	$(1+2\cdot3!)\cdot4$
53	$-1+2\cdot(3+4!)$
54	$(1+2)!^3/4$
55	$1+2\cdot(3+4!)$
56
57
58
59	$-1+2^{3!}-4$
60	$(1+2)!\cdot3!+4!$
61	$1+2^{3!}-4$
62
63	$(1+2)\cdot(-3+4!)$
64
65
66
67	$-1+2^{3!}+4$
68	$1\cdot2^{3!}+4$
69	$1+2^{3!}+4$
70	$-1\cdot2+3\cdot4!$
71	$-1^2+3\cdot4!$
72	$1^2\cdot3\cdot4!$
73	$1^2+3\cdot4!$
74	$1\cdot2+3\cdot4!$
75	$-(1+2)!+3^4$
76
77
78	$-1-2+3^4$
79	$-(1\cdot2)+3^4$
80	$1-2+3^4$
81	$1^2\cdot3^4$
82	$-1+2+3^4$
83	$1\cdot2+3^4$
84	$1+2+3^4$
85
86
87	$-1+2^{3!}+4!$
88	$1\cdot(2^{3!}+4!)$
89	$1+2^{3!}+4!$
90	$(1+2)\cdot(3!)!/4!$
91
92	$(1-(-2+3!)!)\cdot(-4)$
93
94
95	$-1+(2+3)!-4!$
96	$1\cdot(2+3)!-4!$
97	$1+(2+3)!-4!$
98
99
100	$(1+(-2+3!)!)\cdot 4$