About Zeno's paradox and its answers

1.1k Views Asked by At

I read this question How can Zeno's dichotomy paradox be disproved using mathematics? .

The first (ie the one on the top) answer uses the fact that $\sum\limits_{n=1}^\infty\frac{1}{2^n}=1$, because we divided the movement in $1/2+1/4+1/8+...+1/2^n$

However, we could have used another way to decompose the movement: for instance, $1/4+1/9+1/16+...+1/n^2$ etc. However, this sum converges towards $(\pi^2-6)/6<1$

Similarly, we could decompose it using $1/2+1/6+...+1/n!$ whose sum converges towards $e-2<1$.

Therefore, we would never reach the end !

How can we still give an answer to Zeno's paradox with such a decomposition ?

4

There are 4 best solutions below

0
On BEST ANSWER

Zeno's paradox tries to claim that since you need to make infinitely many steps (it does not matter which steps precisely), then it will take an infinite amount of time to get there. The mathematical solution is to sum the times and show that you get a convergent series, hence it will not take an infinite amount of time.

You show above that it is possible to split the length to travel into smaller parts in various ways. But however you will do it the series for the time it will take to traverse these smaller parts will still converge (not necessarily to the time it takes to travel the entire distance, since you may only make it to some mid-point, and then, after you covered countably many little parts, you'll need to continue traveling further). You will only recover the paradox if you could show that you can subdivide the interval in such a way that the time needed to traverse the parts totals to $\infty $. That is impossible though.

2
On

It's easy to see that the traditional "split in half" decomposition covers the entire interval from start (inclusive) to finish (exclusive).

Why should we think the other decompositions you suggested cover the entire interval? If they do not, then we have a nonzero leftover part that happens after all of the steps you listed.

0
On

What you're showing is just how far Zeno's paradox is from a true paradox. What the paradox tries to say is "When you traverse a unit interval, you cover half the remaining distance infinitely many times, so it must not be possible". The implied assumption is that it's not possible to do infinitely many things in the course of accomplishing a task. What you're showing is that, not only is it possible to do infinitely many things, but you may still have work left to do.

0
On

The typical 'solution' to this paradox is convergence. This is when an infinite series converges to a finite amount. Now how can an infinite # of things converge to something finite? Look at 1/3, which is finite. In decimal form, 1/3 is 0.3 repeating, meaning 0.33333333...

So 1/3 = 0.3 + 0.03 + 0.003 + 0.0003 + ... and so on. So an infinite # of terms converge to a finite value of 1/3.

The problem is this does not necessarily correspond with the physical world. Numbers are abstract; they can be divided to no end in the mind, however it does not mean that things made of parts, whether space or time, can keep being divided to no end. If one applies this solution to zeno's paradox, it leads to contradiction.

If zeno has to reach 10 meters, he cannot reach 10 meters until he reaches 5, and he cannot reach 5 until he reaches 2.5, and so on.

So 10 = 5 + 2.5 + 1.25 + 0.625 + ... and so on. So these infinite # of terms converge to 10, a finite amount, so what's the problem with this?

Convergence does not work because at no point do you actually reach the limit, which is 10. You just 'arbitrarily' keep getting closer to it, which really does not solve anything. Imagine there is a flag at each halfway point; one at 5, another at 7.5 (5 + 2.5), another at 8.75 (7.5 + 1.25), and so on. Zeno cannot reach 10 until he collects each flag at each halfway point. How many flags are there? Infinite #. Even with convergence, zeno has to complete an endless # of tasks to reach the goal, and it is contradictory to say zeno finished an endless # of tasks. Atomizing spacetime would solve the problem, that spacetime can be divided only a finite # of times, and there is a smallest part, a building block, if you will.