Absolute value of sum of additive characters of $\mathbb{F}_p$

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Consider the absolute value of the following exponential sum:

$\left|\sum_{x \in \mathbb{F}_p} \sum_{y \in \mathbb{F}_p}e^{\frac{2\pi i}{p}(ux+vy-wxy)}\right|$

for given $u,v,w\in\mathbb{F}_p$ with $w \neq 0$.

Through computer experimentation I have observed that this is always equal to $p$, but I am unable to prove this for the case where both $u \neq 0$ and $v \neq 0$.

Why is this true? And if it is not, is there a counterexample?

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Expand $(1+ax)(b+vy)$ and identify with $b+ux+vy-wxy$, assuming that $u\ne 0,v\ne 0$.

So $a\ne 0,v\ne 0$ and it is immediate that $$\sum_{x \in \mathbb{F}_p} \sum_{y \in \mathbb{F}_p}e^{\frac{2\pi i}{p}(1+ax)(b+vy)} =p$$