absolutely integrable f with existing non-zero limit at infinity

450 Views Asked by At

I'm looking for an example of f(x) which is absolutely integrable but its limit at positive infinity exists and is not zero.

$$\int_{-\infty}^{\infty}|f(x)|dx< \infty$$ $$\lim_{x \to \infty} f(x)= L\neq 0$$

I know if f'(x) is continuous then the limit at infinity is zero. And there are examples using series where the limit does not exist.

Without considering the existence of f'(x), Is there such function that satisfies the conditions above?

If there is no such function how can I prove it?

1

There are 1 best solutions below

0
On BEST ANSWER

There's no such functions: $|f(x)| > \frac{L}2$ for $x > x_0$ and $\int_{\mathbb{R}} | f(x)|dx \ge \int_{x>x_0} | f(x)|dx \ge \int_{x>x_0} L dx = \infty$.

There are integrable functions, such that $\overline{lim}_{x \to \infty} f(x) dx = L > 0$. E.g. $f(x) = \sum_{n \ge 1} I\{ n \le x \le n+2^{-n} \}$.