Your write ups could do with some formalizing and cleaning up; you are on the right track for your second inclusion. For the first inclusion, we take some permutation $\tau$ for which $\tau(TOP)=HAT$, and we must decompose it as
$$
\tau=\sigma\rho,\rho\in Stab(TOP).
$$
To this hand, note that since $\sigma(TOP)=HAT$, we must have $\sigma^{-1}(HAT)=TOP$. Thus
$$
\sigma^{-1}\tau(TOP)=\sigma^{-1}(HAT)=TOP,
$$
so $\sigma^{-1}\tau\in Stab(TOP)$. Can you finish from here?
Your write ups could do with some formalizing and cleaning up; you are on the right track for your second inclusion. For the first inclusion, we take some permutation $\tau$ for which $\tau(TOP)=HAT$, and we must decompose it as $$ \tau=\sigma\rho,\rho\in Stab(TOP). $$ To this hand, note that since $\sigma(TOP)=HAT$, we must have $\sigma^{-1}(HAT)=TOP$. Thus $$ \sigma^{-1}\tau(TOP)=\sigma^{-1}(HAT)=TOP, $$ so $\sigma^{-1}\tau\in Stab(TOP)$. Can you finish from here?