I've already asked a question similar to this but this one is more difficult and plus want to make sure I'm understanding this correctly.
I've got this equation below:
$$ \begin{bmatrix} 2 & 0 & -1 \\ 4 & -5 & 2 \\ \end{bmatrix} + 2* \begin{bmatrix} 7 & -5 & 1 \\ 1 & -4 & -3 \\ \end{bmatrix} $$
I believe it is solved like so:
$$ \begin{bmatrix} 2 & 0 & -1 \\ 4 & -5 & 2 \\ \end{bmatrix} + \begin{bmatrix} 14 & -10 & 2 \\ 2 & -8 & -6 \\ \end{bmatrix} $$
$$ \begin{bmatrix} 16 & -10 & 1 \\ 6 & -13 & -4 \\ \end{bmatrix} $$
Am I doing the addition right? Add both row 1's together then both row 2's together. For example, it would look something like this, when adding:
$$ \begin{bmatrix} 2+14 & 0-10 & -1 + 2 \\ 4+2 & -5-8 & 2+-6 \\ \end{bmatrix} $$
EDIT: caught an addition error I made with the 2 + 14 for my final answer. Originally I had 28 down because I was multiplying but I think what I want is 16.
Robert Howard, per your request:
Everything there is correct.
Matrices are vectors and follow the identical rules for addition and scalar multiplication.