Algebra simplification involving power

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I'm taking a statistics course and reading notes this equation :

$$ \frac{1-n}{2}(1-2t)^{\frac{1-n}{2}}(-2) $$

is simplified to :

$$ (n-1)(1-2t)^{\frac{-1-n}{2}} $$

Simplification I've calculated is result of multiplying

$$ \frac{1-n}{2}(1-2t)^{\frac{1-n}{2}} $$

by -2 :

$$ \frac{1-n}{2}(2+4t)^{\frac{1-n}{2}} $$

How is more simpler version :

$$ (n-1)(1-2t)^{\frac{-1-n}{2}} $$

arrived at ?

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Just: $$\frac{1-n}{2}(1-2t)^{\frac{1-n}{2}}(-2)=\left((-2)\cdot\frac{1-n}{2}\right)(1-2t)^{\frac{1-n}{2}}=(n-1)(1-2t)^{\frac{1-n}{2}}.$$