Algebra Word Problem - Distance between two towns

Question

How would I find the answer to the attached question?

A freight train is $27$ minutes late when it makes its usual trip between town A Trinhland and Town B Jafferton at an average speed of $56$ km/hr. For another trip between Town A and B, the freight train is $42$ minutes late when its average speed is $54$ km/hr. What is the distance between Town A and Town B?

Answer 1

I believe this is an approach:
$d=v_1*t=v_2*(t+15/60)$
$v_1*t-v_2*t=v_2*0.25$
$t(v_1-v_2)=v_2*0.25$
$t = v_2*0.25/(v_1-v_2)$

$d=v_1*v_2*0.25/(v_1-v_2)$

I hope this helps.

Answer 2

Distance =time *speed If time taken by train from place A to B = x hours From case 1-- distance between A and B = 56(x+27/60) From case 2-- Distance b/w A and B= 54(x+ 42/60) From case 1 and case 2 56(x+27/60)=54(x+42/60) X=27*14/60 Put the Vale of x in case 1 D= 56(27*14/60 + 27/60) =56*27*15/60 = 378 km