Algebraic manipulation of matrices

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I'm trying isolate for X in the function, but I'm making an error that I can't find where exactly I've gone wrong. $A,B,C,D $ and $X$ are all n x n matrices. Here are my steps.

$$AX(D+BX)^{-1} = C$$

Multiply $(D+BX)^{-1}$ to both sides

$$AX = (D+BX)C$$

Expand

$$AX = DC+BXC$$

Subtract $BXC$

$$AX - BXC = DC$$

Factor X

$$X(A - BC) = DC$$

Multiply by the inverse of $(A-BC)$ And end with

$$X = (A-BC)^{-1}DC$$

I am uncertain about some of the operations I'm performing and their legality, such as the factoring of X and multiplying by both sides correctly. Any help is appreciated, Thank you!

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It looks to me like your main error lies in assuming matrices commute when they don't in general. For example, the equation

$AX(D + BX)^{-1} = C \tag 1$

implies

$AX = C(D + BX), \tag 2$

but not necessarily

$AX = (D + BX)C; \tag 2$

similarly,

$AX - BXC = DC \tag 3$

does not typically imply

$X(A - BC) = DC, \tag 4$

since $X$ usually won't commute with $A$ or $B$:

$XA \ne AX; \; XB \ne BX. \tag 5$

These issues may be avoided as follows:

from (1),

$AX = C(D + BX); \tag 6$

then

$AX = CD + CBX, \tag 7$

or

$(A - CB)X = CD; \tag 8$

if now we know--or assume--that $A - CB$ is invertible, we have

$X = (A - CB)^{-1}CD. \tag 9$