I'm getting a really large angle when I work out this problem and I'm not sure why. I have a plane which has the equation: $0.19x-0.68y+0.7x = -2.19$. I took a point which is on the plane and called it $Q$ (in this example it's the center of the hexagon) along with the point S to compute vector $\mathbf Q \mathbf S$. In the schematic, $r$ would just be the magnitude of $\mathbf Q \mathbf S$ and in order to find $\theta$ I would use the following equation: $cos \theta =\left(\frac{\mathbf n \cdot \mathbf Q\mathbf S}{\mathbf {\vert \mathbf n \vert} \cdot {\mathbf {\vert Q \mathbf S \vert}}} \right) $ where $ \mathbf n $ is $<0.19, -0.68, 0.7>$. Am I approaching this correctly?
