Hi I'm sorry to ask another question so soon but I'm unaware of what the following notation means. Again this is taken from a Combinatorics context.
It looks like this: $\begin{Bmatrix} n\\ n-1 \end{Bmatrix}$
I'm told it is equal to $n\choose 2$
EDIT: The question in hand: Find a number $n>2$ such that n and $\begin{Bmatrix} n\\ n-1 \end{Bmatrix}$ have different parity.
Thanks for any help.
It may be the Stirling number of the second kind.