Here's a problem that I'm stuck on:Consider the paper triangle whose vertices are $(0,0), (34,0),$ and $(16,24).$ The vertices of its midpoint triangle are the midpoints of its sides. A triangular pyramid is formed by folding the triangle along the sides of its midpoint triangle. What is the volume of this pyramid?
In the solution, it says that the apex of the pyramid is directly above the orthocenter of $\triangle{ABC}$, which I don't get. This is really obvious if the tetrahedron was regular, because then the projection would be directly above the center of the triangle which includes the orthocenter.
Any explaining would be great. Thanks.