Applaying equivalence of norms to show a sequence is a Cauchy sequence

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Let $\|\cdot\|$ be any norm on $\mathbb R^n$ prove that a sequence $x \in \mathbb R^n$ is a Cauchy sequence under $\|\cdot\|_2$ if and only if it is a Cauchy sequence under any $\|\cdot\|$.

I tried following this link in wiki and this post with a very similar question.

I want to use the system from the post and say for a Cauchy sequence $|x_m-x_n|<\varepsilon$ and therefor $\|x_m-x_n\|_1<\varepsilon$, and then use $c\|x_m-x_n\|_2\leq \|x_m-x_n\|_1\leq d\|x_m-x_n\|_2$.

Can i say that if $|x_m-x_n|<\varepsilon$ (from wiki) then the norm is also smaller then $\varepsilon$ that is: $\|x_m-x_n\|<\varepsilon$.

Can I apply the same system as used in the post in this case? if not what will be a good way to prove this?

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Hint: Show that if $E$ is a vector space finite dimensional then all norms in $E$ are equivalents, i.e., if $\|\cdot\|_1$ and $\|\cdot\|_2$ are norms in $E$ then there are $c_1,c_2 >0$ constants such that

$$c_1 \|x\|_1\le\|x\|_2\le c_2\|x\|_1$$

for every $x\in E.$