Are integrally closed domains Dedekind domains?

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A domain $D$ is integrally closed if it is integrally closed in its field of fractions $F$. A Noetherian ring may not be integrally closed; for example, $\mathbf{Z}\sqrt{5}$ is Noetherian but it is not integrally closed in its field of fractions $\mathbf{Q}\sqrt{5}$.

It is said that every Dedekind domain is integrally closed. Does the converse hold, namely are integrally closed domains Dedekind Domains?

The only example of an integrally closed domain that I have is the ring of integers and the examples of a Dedekind domain are PID and the ring of integers of a number field. May you please provide an example of an integrally closed domain which is not Dedekind?

Would you help me, please? Thank you in advance.

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No. Among many characterisations, Dedekind domains are noetherian integrally closed domains of Krull dimension $1$, i.e. every non-zero prime ideal is maximal.

As a simple counter example, if $K$ is a field, the ring of polynomials $K[X_1,\dots, X_n]$ is a noetherian integral domain of Krull dimension $n$.

Furthermore, a valuation domain of dimension (height) $1$ is integrally closed (as all valuation domains), but it is not necessarily a Dedekind domain, as it is not necessarily a discrete valuation domain.