Are maximal Ideals in $\mathbb{Z}[\sqrt 2]$ equal when their quotient rings are isomorphic?

245 Views Asked by At

Let $R = \mathbb{Z}[\sqrt 2]$ and $M_1,M_2 \subset R$ be maximal ideals.

Prove or disprove: If $R/M_1$ isomorphic to $R/M_2$ then $M_1=M_2$.

1

There are 1 best solutions below

1
On BEST ANSWER

Hint: Consider $M_1 = (3 - \sqrt{2})$ and $M_2=(3 + \sqrt{2})$.