Can you prove if no or give an example if yes?
Obviously, this should be an example of an infinite-dimensional space, since in a finite-dimensional space, any two norms are equivalent.
Can you prove if no or give an example if yes?
Obviously, this should be an example of an infinite-dimensional space, since in a finite-dimensional space, any two norms are equivalent.
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On the space $X$ of finitely non-zero sequences let $\|(x_n)\|_1=\sum a_n|x_n|$ and $\|(x_n)\|_2=\sum b_n|x_n|$ where $a_n>0$ and $b_n >0$ for all $n$. These are norms on $X$. Neither is sub-ordinate to the other if neither $\frac {a_n} {b_n}$ nor $\frac {b_n} {a_n}$ is bounded. I will let you construct such sequences.
Detailed solution: Take $a_n=1$ for $n$ even and $n$ for $n$ odd, $b_n=n$ for $n$ even and $1$ for $n$ odd. Prove by contradiction that inequalities like $\|.\|_1 \leq C \|.\|_2$ and $\|.\|_2 \leq C \|.\|_1$ cannot hold. If the first inequality holds put $(x_n)=e_n$ to see that $|a_n| \leq C|b_n|$ which is a contradiction. Second case is similar.