I was given a question that resulted in the following equation:
$$ \cos(90°) = \frac{-10 + p}{\sqrt{11} \cdot \sqrt{20+p}}$$ Since $\cos(90°) = 0$, the equation becomes: $$ 0 = \frac{-10 + p}{\sqrt{11} \cdot \sqrt{20+p}}$$
Wouldn't multiplying the denominator in this case cause us to lose roots? Can someone please elaborate on this – when can we do what?
For $0=a/b$, the only solutions have $a=0, b\ne 0$. By multiplying to get $0=a$, you do not lose roots. You may gain roots if it could happen that $a=b=0$.
For example, $0=x/x$ has no solution, but multiplying by $x$ we get $0=x$, which does have a solution.