$\triangle OAB$ has virtices $A(0,12)\;\;,B(5,0)\;\;,O(0,0)$. There exists a line $l$ cutting $AB$ and $OA$ at $M$
and $N$ respectively such that thses circle can be inscribed in $\triangle AMN$ and quadrilateral $OBMN$
also these two circle are tangent to the line $l$ at the same point. If line passess through $(0,-8)\;,$
Then area of quadrilateral $OBMN$ is
$\bf{My\; Try::}$ Let Equation of line be $y-0 = m(x+8)\Rightarrow y=m(x+8)\;,$ Where $m$ is slope.
Now equation of line $AB$ is $12x+5y=60$
Now how can i solve it, Help required, Thanks