please help me solve this :-
prove that area of section of cone $$ bcx^2 + cay^2 + abz^2 = 0 $$ by the plane $$ lx+my+nz = p $$ is
$$\frac{\pi p^2 \sqrt{abc}}{(al^2 + bm^2 + cn^2)^{3/2}}$$
please help me solve this :-
prove that area of section of cone $$ bcx^2 + cay^2 + abz^2 = 0 $$ by the plane $$ lx+my+nz = p $$ is
$$\frac{\pi p^2 \sqrt{abc}}{(al^2 + bm^2 + cn^2)^{3/2}}$$
Copyright © 2021 JogjaFile Inc.