Area of section of cone cut by the plane

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please help me solve this :-

prove that area of section of cone $$ bcx^2 + cay^2 + abz^2 = 0 $$ by the plane $$ lx+my+nz = p $$ is

$$\frac{\pi p^2 \sqrt{abc}}{(al^2 + bm^2 + cn^2)^{3/2}}$$