In Triangle $DEF$, $P$ is mid point of $EF$ and $Q$ is the midpoint of $DP$. The area of triangle $DQF$ is $6 \ cm^2$. We need to find the area of triangle $EQF$.
I tried many ways to solve it but could only conclude that area of triangle $DEP$ and $DPF$ are the same. I could not proceed from there. How do I find the area of $EQF$?
Hint:
Let $FH$ the height of the triangle $DQF$ for the basis $DQ$. It is the height also of the triangle $PFQ$ and, since $DQ=PQ$ these two triangle have the same area.
Now do the same reasoning for the triangles $PFQ$ and $PEQ$.