Is there another perfect number $n$ besides 6 such that $n'<n$, where $n'$ is the arithmetic derivative?
2026-03-26 02:26:05.1774491965
Arithmetic derivative perfect number
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$6$ is the only such even number.
The only even perfect numbers are $2^{p-1}(2^p-1)$ where $2^p-1$ is prime.
Suppose $p\ge3$, the derivative is then $(p-1)2^{p-2}(2^p-1)+2^{p-1}$ and this is greater than $2^{p-1}(2^p-1)$.