I have faced an equation that I just cannot solve. I know that it must be solved using geometric progression sum forumla, but I don't know how to find the difference. Maybe you could help me? :) $$ \dfrac{1}{x+x^2+\cdots} = \dfrac{7}{2}$$, if $$0< x < 1$$
2026-04-09 00:46:19.1775695579
Arithmetic progression sum equation
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Hint: $x+x^2+\cdots = x(1+x+\cdots) = \dfrac{x}{1-x} = \dfrac{2}{7}$