8 children can do a work in 12 days whereas 6 adults can do it in 8 days. If among 12 adults ,8 adults leave work, 2 days after starting a work and 16 children join work instead. Then how many days will it take to do the rest work?
I can't solve it. I have tried for 2 hours. Please help me to find out the solution.
In $12$ days $8$ children will complete $12 \times 8 = 96$ child-days of work.
In $8$ days $6$ adults will complete $8 \times 6 = 48$ adult-days of work.
So $96$ child-days is the same as $48$ adult-days. In other words, $2$ children work at the same rate as $1$ adult.
So the $16$ children who join the team are working at the same rate as the $8$ adults who left after $2$ days.
I'll let you take it from there.