This question is about addition of positive integers with more than one digit, a topic covered in second grade. But it's not really elementary.
But first we need to introduce the positive integers $\mathbb N$ the way a second grader conceives them. Of course they will not think of $\mathbb N$ as the set defined by the Peano axioms. Instead, we start with the 10 symbols $A=\{0,1,2,\ldots,9\}$ and we $\bf define$ a positive integer to be a finite string $a_na_{n-1}\cdots a_1a_0$ where each $a_i\in A$ (and they are not all zero). Then we define the operation of addition by the usual algorithm involving carries that is taught in second grade. Here is my question: prove that this operation is associative. Disclaimer: I know how to prove it, but surely my proof could not be explained to a second grader. I would like to know if there is a really elementary proof.
The addition algorithm involving carries should be a theorem, not a definition, even for a 2nd grader. Addition should be defined semantically, and the obvious way to do it at the 2nd grade level makes associativity obvious: if Alice, Bob, and Carol have $a, b, c$ apples, and they pool their apples together, they have $a + b + c$ apples.
I write this without parentheses because this operation does not involve any parentheses: "pool their apples together" is an $n$-ary operation that immediately makes sense without any reference to a binary operation. Other intuitive forms of counting and addition could be used here: for example, Alice, Bob, and Carol might be carrying three sticks of lengths $a, b, c$, and then I'd tell you to line those sticks up to produce a bigger stick of length $a + b + c$ (note that this makes commutativity a little less obvious). Or Alice, Bob, and Carol might be carrying three rocks of weight $a, b, c$, etc.
Then it is, again, a theorem that this operation reduces to binary addition, and that either parenthesization works. Alice, Bob, and Carol can pool their apples together either by having Alice and Bob pool their apples together first, then Carol, or by having Bob and Carol pool their apples together first, then Alice. This gives
$$a + b + c = (a + b) + c = a + (b + c)$$
as desired. The point of presenting the argument this way is that $(a + b) + c$ and $a + (b + c)$ are equal because they are equal to a third operation, which is "add three things." Other associativity arguments in mathematics can be written to work exactly the same way (e.g. associativity of the tensor product).