Given that the positive integers $a,b,c,$ and $d$ satisfy $\cfrac{a}{b}<\cfrac{c}{d} < 1 $,arrange the following in order of increasing magnitude :$$\cfrac{b}{a},\cfrac{d}{c},\cfrac{bd}{ac},\cfrac{b+d}{a+c},1$$
My attempt
I've been able to get three of them in position ,namely $$\cfrac{bd}{ac} >\cfrac{b}{a}>\cfrac{d}{c}>1$$ since it's given that $\cfrac{a}{b} < \cfrac{c}{d}$ from which I have that $\cfrac{b}{a}>\cfrac{d}{c}$ and since $\cfrac{b}{a},\cfrac{d}{c} >1$ I have that $\cfrac{bd}{ac} >\cfrac{b}{a}>\cfrac{d}{c}>1$.
Now I am kind of clueless on how to tackle the expression $\cfrac{b+d}{a+c}$,as I don't see how I can get this by manipulating any of the given relations.
From $$ b = a \frac ba > a \frac dc $$ it follows that $$ \frac{b+d}{a+c} > \frac{a \frac dc+d}{a+c} = \frac dc $$ and in a similar way you get $$ \frac{b+d}{a+c} < \frac ba \, . $$
There is also a general theorem which states that for positive numbers, $$ \min \frac{a_i}{b_i} \le \frac{a_1 + ... + a_n}{b_1 + ... + b_n} \le \max \frac{a_i}{b_i} $$ and this is proved using the same ideas.