I have a question regarding integration of a (continuous) function $f(x)\in C[a,b]$. Of course, by the second fundamental theorem of calculus, $$\int_a^b f(x) \ dx=F(a)-F(b)$$ I am wondering if there are any assumptions or circumstances in which this is equivalent to $F(a-b)$?
Thanks in advance.
Yes. If it turns out that $f$ a constant function, then $F$ is an affine map and therefore $F(a)-F(b)=F(a-b)$.