How to sketch the graph of $\ln (3x+2)$
I know that the x intercept is $\frac{-1}{3}$ and y intercept is $0.7$ . But for a logarithm graph, the asymptote of the graph is $x=$ something. For example, I know that the graph of $\ln (x-2)$ has an asymptote at $x=2$ because the graph is shifted to the right by 2 units. But what about $\ln (3x+2)$ ? I cannot just say that the graph shifts to the left by 2 and thus the asymptote is at $x=-2$, how do I find where’s the asymptote for this graph ?
$\ln(x)$ has an asymptote at $x= 0$, since $\ln(0)$ is undefined. So, for what value of x is $3x+2=0$?