I apologise if this question is ill-formed or too broad. It's just for fun. I've thrown in the soft question tag for good measure.
Let $G=\langle X\mid R\rangle$ be a group. What can be said in relation to $G$ about the automaton $\mathcal{A}(G)$ whose accepted language over the alphabet $X\cup X^{-1}$ is (the set of relators) $R$?
It's a long time since I've done anything with formal languages and automata, so please forgive me as I just point out one obvious feature as my input.
If $G$ is finitely presented, then $\mathcal{A}(G)$ is a finite state automaton.
In general, I think that you really want to talk about the automata accepted by the elements of $\langle\langle R\rangle\rangle\leq F(X)$ (where $\langle\langle R\rangle\rangle$ denotes the normal closure of the set $R$). This is because we can change the relators really easily, but this subgroup is somehow more rigid. The elements of this subgroup form a language, often referred to as "the word problem", and of course languages and automata are related.
Theorem. (Muller-Schupp, 1983) A finitely generated group $G=\langle X; R\rangle$ has context free word problem (that is, elements of $\langle\langle R\rangle\rangle$ form a context free language) if and only if the group $G$ is virtually free.
That is, the automata $\mathcal{A}$ which accepts precisely the set of elements $\langle\langle R\rangle\rangle\leq F(X)$ is a pushdown automata if and only if the group contains a free subgroup of finite index.
This theorem is super-important. It says that we can gain algebraic information about groups by understanding their languages of word problems, and vice-versa. It plays a similar strategic role to Gromov's theorem on groups of polynomial growth, which says that we can gain algebraic information about groups by understanding their coarse geometries, and vice-versa.